Question

разложить на множители 4-16а"2, 9в"5-в"3

Answer 1

4-16а^2=(2-4a)(2+4a)
9b^5-b^3=b^3(9b^2-1)=b^3(3b-1)(3b+1)

Answer 2

4-16а^2=(2-4a)(2+4a)
9b^5-b^3=b^3(9b^2-1)=b^3(3b-1)(3b+1)