Question

Срочно! Упростите выражение.Помогите решить.
$( \frac{6}{ y^{2}- 9} + \frac{1}{3 - y}) * \frac{ y^{2}+6+9 }5}.$

Answer 1

$( \frac{6}{y^2-9} + \frac{1}{3-y})\times \frac{y^2+6y+9}{5} = (\frac{6}{(y-3)(y+3)}- \frac{y+3}{(y-3)(y+3)} )\times \frac{(y+3)^2}{5} = \\ =\frac{-(y-3)}{(y-3)(y+3)} \times \frac{(y+3)^2}{5}=- \frac{y+3}{5}$