Предмет: Алгебра, автор: nopa

Найдите сумму квадратов абсцисс точек пересечений графиков функций  пример во вложении

Приложения:

Ответы

Автор ответа: rokfeller007
0

Получим:

|x-1|-5=0

|x-1|=5

1)x-1=5

x=6

2)x-1=-5

x=-4

 

6^2+(-4)^2=36+16=52

 

Ответ:52

Автор ответа: Аноним
0

Исходя из графика видно, что x1^2+x2^2=(-4)^2+6^2=16+36=52

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Приложения:
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