Question

[tex] \frac{х+2,4}{7} = [tex] \frac{х-0,3}{3,5}

Answer 1

$\frac{x+2,4}{7} = \frac{x-0,3}{3,5}$

$3,5(x+2,4)=7(x-0,3)$
$3,5x+8,4=7x-2,1$
$3,5x-7x=-2,1-8,4$
$-3,5x=-10,5$ |*(-1)
$3,5x=10,5$

$x= \frac{10,5}{3,5} * \frac{10}{10} = \frac{105}{35} = 3$