Question

3x^2-(7xy-4x^2)+(5xy-7x^2)при x=0,3, при y=-10

Answer 1

$3x^2 -(7xy-4x^2)+(5xy-7 x^2) \\ 3*0.3^2-(7*0.3*(-10)-4*0.3^2)+(5*0.3*(-10)-7*0.3^2) \\ 0.27-(-21-0.36)+(-15-0.63) \\ 0.27-(-21.36)+(-15.63) \\ 0.27+21.36-15.63=6$