Question

cos9x-cos7x+cos3x-cosx=0

Answer 1

(cos 9x - cos x) = (cos 7x - cos 3x)
- 2 sin [(9x+x)/2] * sin [(9x-x)/2] = - 2 sin [(7x+3x)/2] * sin [(7x-3x)/2]
sin 5x * sin 4x = sin 5x * sin 2x
sin 4x = sin 2x
2 sin 2x * cos 2x = sin 2x
2 cos 2x = 1
cos 2x = 1/2
2x = п/3 = 60 град.
x = 60/2 = 30 град.