Question

$Log _{2} 16+Log _{1/3} 9 \\ 5 ^{Log _{5}10-1 }$

Answer 1

$log_216+log_ \frac{1}{3}9=log_22^4+log_{3^{-1} }3^2=4*1+(-2log_33)=4-2=2 \\ 5^{log_510-1}= \frac{5^{log_510}}{5^1}= \frac{10}{5}=2$