Question

производная sinx/lnx x0=e

Answer 1

$y'= \frac{\sin x}{\ln x}\\\\ = \frac{\sin x'*\ln x - \sin x* \ln x'}{\ln^2 x} = \frac{\cos x\ln x- \frac{\sin x}{x} }{\ln^2 x}= \frac{x\cos x\ln x-\sin x}{x\ln^2 x}$

$\frac{e*\cos e*\ln e-\sin e}{e*\ln^2 e}= \frac{e*\cos e -\sin e}{e}$