Question

1)f (x)=18x-6+3x^2+4x^3
2)g'(x)=4x+5/8x-2
g'(2)=
g'(-1)=
3)h (x)=(2+3)^5
4)4 (x)=(x^2+8)×(x-4)
5)f (x)=2 cos 4x
f'(Пи/2)=

Answer 1

g(2)=13/14 g(-1)= -0,1 f(π/2)= 2