Question

решите пожалуйста


2-5y + 2y2 - 5y3 = ...
4z - 3 - 3z2 + 4z3 = ....
7× 630 + 6 × 630 + 4 × 137 = ...

Answer 1

1)(2-5у)+y^2(2-5y)=(2-5y)(1+y^2)
2)(4z-3)-z^2(3-4z)=(4z-3)+z^2(4z-3)=(4z-3)(1+z^2)
3)630(7+6)+4*137=630*13+4*137=8190+548=8738