Question

107.14 Найдите производную функции (х≠2) $f(x)= frac{3x^6-6x^5-20x^4+40x^3}{x-2}$

Answer 1

$(x^n)'=nx^{n-1}$

$f(x)= frac{3x^6-6x^5-20x^4+40x^3}{x-2} =frac{3x^5(x-2)-20x^3(x-2)}{x-2}= \ =frac{(x-2)(3x^5-20x^3)}{x-2} =3x^5-20x^3 \ f'(x)=15x^4-60x^2$