Question

сos(п/2 -t) - sin(п+t) = √2

Answer 1

сos(п/2 -t) - sin(п+t) = √2    |

                                             |=>√2= 2sin(t)=>t∈{2πK+3π/4;2πK+π/4}

сos(п/2 -t) - sin(п+t) = 2sin(t)|

Answer 2

$cos(frac{pi}{2}-t)-sin(pi+t)=sqrt{2};\ sin t +sin t=sqrt{2};\ 2sint =sqrt{2};\ sin t=frac{sqrt{2}}{2};\ t=(-1)^k *frac{pi}{4}+pi*k$

k є Z