Question

решите 11a-99b
5a-3ab
3aво2-6ab
bв7+bв4

Answer 1

$11a-99b=11(a-9b)\3ab^2-6ab=3ab(b-2)\b^7+b^4=b^4(b^3+1)=b^4(b+1)(b^2-b+1)$