Question

Решите уравнение:
(x-4)²-x²=12
25y²-1-(5y-2)²=0

Answer 1

x²-8a+16-x²=12      25y²-1-25y²+20y-4=0
-8a+16=12             20y-5=0
-8a=-4                   20y=5   
a=0,5                     y=0,25

Answer 2

(x-4)^2-x^2=12
x^2-8x+4-x^2=12
-8x+4=12
-8x=8
x=-1


25y^2-1-(5y-2)^2=0
25y^2-1-(25y^2-20y+4=0
25y^2-1-25y^2+20y-4=0
-1+20y-4=0
-5+20y=0
20y=5
y=4