Предмет: Математика, автор: annaaniarmen

Определите наибольшее и наименьшее значения функции y=2x^3+3x^2-1 на отрезке от -1 до 2

Ответы

Автор ответа: ILOVENY

y=2x^3+3x^2-1
y" = 6x² + 6 x, (y" - производная)
6x²+6x=0
6x(x+1)=0
6x=0 или х+1=0
х=0 х=-1
y(-1) = -2 + 3 -1 = 0
y(0) = -1 - наименьшее значение
y(2) = 16 + 12 - 1 = 27 - наибольшее значение

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