Question

решиите систему уравнений
{х-3y = 2
{хy + y =6

Answer 1

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Answer 2

{x-3y=2⇒x=3y+2
{xy+y=6
(3y+2)y+y-6=0
3y²+3y-6=0
y²+y-2=0
y1+y2=-1 U y1*y2=-2
y1=-2⇒x1=-2*3+2=-4
y2=1⇒x2=3*1+2=5
(-4;-2);(5;1)