Предмет: Геометрия, автор: Диснеей

Периметр равностороннего треугольника равен 108√3. Найдите его высоту

Ответы

Автор ответа: Аноним

у равностороннего треугольника все стороны равны. а значит периметр треугольника Р=3а. Отсюда сторона а=Р/3=108√3/3=36√3 .
Так как у равностороннего треугольника все углы по 60 гр, то с прямоугольного треугольника высота: h=asin60=36√3 * √3/2 = 54

Ответ: 54.

Автор ответа: Диснеей

Спасибо)

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