Question

решите уравнения a^3+a^2-4a-4=0 x^3+3x^2-4x-12=0 9x-x^3+9-x^2=0 2a^3-8a+6a^2-24=0 y^3+4-y^2-4y=0

Answer 1

a^2(a+1)-4(a+1)=0
(a-2)(a+2)(a+1)=0
a=+-2
a=-1
x^2(x+3)-4(x+3)=0
(x-2)(x+2)(x+3)=0
x=+-2
x=-3
-x^2(x+1)+9(x+1)=0
(3-x)(3+x)(x+1)=0
x=+-3
x=-1
y^2(y-1)+4(y-1)=0
(y^2+4)(y-1)=0
y=1