Предмет: Алгебра, автор: xNeo1x

Помогите решить: (6y-7)^2-(9y+4)^2

Ответы

Автор ответа: Rechnung

0

В задании отсутствует условие и непонятно, что надо сделать: разложить на множители или же представить в виде многочлена, поэтому делаю оба варианта.
$(6y-7)^2-(9y+4)^2=(6y-7+9y+4)(6y-7-9y-4)=\=(15y-3)(-3y-11)\\(6y-7)^2-(9y+4)^2=36y^2-84y+49-(81y^2+72y+16)=\=36y^2-84y+49-81y^2-72y-16=-36y^2-156y+33$

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