Question

6a/4-9a^2+1/3a-2
Это дробь решите плииз)

Answer 1

$\ frac{6a}{4-9a^2} + frac{1}{3a-2} = frac{6a}{(2-3a)*(2+3a)} - frac{1}{2-3a} = frac{6a-1*(2+3a)}{(2-3a)*(2+3a)} = frac{6a-2-3a}{(2-3a)*(2+3a)} = \ = frac{3a-2}{(2-3a)*(2+3a)} = - frac{3a-2}{(3a-2)*(3a+2)} =- frac{1}{3a+2}$