Предмет: Математика, автор: arkangav

Помогите умоляю!!!
x^2(3x-2)(5x-1)^4>=0

Ответы

Автор ответа: dnepr1
0
Функция  x^2(3x-2)(5x-1)^4>=0 -  это произведение трёх составляющих.
Каждое из них может быть равно 0:
х² = 0    х₁ = 0.
3х - 2 = 0     х₂ = 2/3.
(5x-1)^4 = 0    5x-1 = 0     х₃ = 1/5.
Обобщающим является 
х₂ = 2/3.
Поэтому ответ х  2/3.

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