Предмет: Физика, автор: gorynich

Помогите пожалуйста, с подробным решением ( и с рисунком если он нужен)
Предмет находится перед рассеивающей линзой на расстоянии mF (где F — ее фокусное расстояние). На каком расстоянии от линзы получится мнимое изображение и во сколько раз оно будет меньше самого предмета?

Ответы

Автор ответа: MashaPutnaj

Дано d=m*IFI F<0 ( так как линза рассеивающая)
f- ?
1/d-1/f=-1/F
1/f=1/m*F+1/F=(1+m)/m*F
IfI=m*F/(m+1) - ответ
h/H=d/f=m+1 - ответ

Автор ответа: MashaPutnaj

Это ваше раво. Пока

Автор ответа: gorynich

Ответьте пожалуйста, здесь рисунок нужен ?

Автор ответа: MashaPutnaj

не повредит, если у умеете строить, но можно и без рисунка потому что m не дано

Автор ответа: gorynich

Спасибо!

Автор ответа: MashaPutnaj

рассеивающая линза всегда дает изображение МНИМОЕ, ПРЯМОЕ УМЕНЬШЕННОЕ

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