Предмет: Физика, автор: дойка123

определите жёсткость пружины динамометра если расстояние между делениями его шкалы 0 и 1 равна 2 см

Ответы

Автор ответа: Armenui

0

Fт- сила тяжести

Fу-сила упругости

Если рассматривать от 0 до 1 2 см тогда

Fт=1H

Fу=1H==k*0,02;

k=50H/m

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