Question

x^4-3x²-10=0 ; x-5√x+6=0
Решите пожалуйста два уравнения

Answer 1

$x^{4}-3x^{2}-10=0\ x^{2}=t\ t^{2}-3t-10=0\ t_{1}+t_{2}=3\ t_{1}t_{2}=-10\ t_{1}=-2\ t_{2}=5\ x^{2}=-2 to varnothing\ x^{2}=5 to x=pmsqrt{5}$

Ответ: $pm sqrt{5}$.

$x-5sqrt{x}+6=0\ (sqrt{x})^{2}-5sqrt{x}+6=0\ sqrt{x}=t\ t^{2}-5t+6=0\ t_{1}+t_{2}=5\ t_{1}t_{2}=6\ t_{1}=3\ t_{2}=2\ sqrt{x}=2 to x=4\ sqrt{x}=3 to x=9$

Ответ: 4, 9.

Answer 2

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