Question

Решить задание №2 и №3

Answer 1

$ax^{2}+bx+c=a(x-x_{1})(x-x_{2})\ \ x^{2}-x-6=0\ x_{1}+x_{2}=1\ x_{1}x_{2}=-6\ x_{1}=-2\ x_{2}=3\ x^{2}-x-6=(x+2)(x-3)\ \ x^{2}+px-1=0\ x_{1}+x_{2}=-p\ x_{1}x_{2}=-1\ 2x_{2}=-1\ x_{2}=-0,5\ x^{2}-1,5x-1=0$