Question

Выполнить действие (√14-3√2)^2+6√28

Answer 1

$(sqrt{14}-3sqrt{2})^2+6sqrt{28}=\ (sqrt{14})^2-2*sqrt{14}*(3sqrt{2})+(3sqrt{2})^2+6sqrt{28}=\ 14-6sqrt{14*2}+3^2*2+6sqrt{28}=\ 14-6sqrt{28}+18+6sqrt{28}=\ 14+18=32$