Question

помогите решить 4sin^2x=cos^2x

Answer 1

$4sin^2x=cos^2x|:sin ^2x \ tg^2x=4 \ left[begin{array}{ccc}tgx=-2\ tgx=2end{array}right \ \ left[begin{array}{ccc}x_1=-arctg 2+ pi n, n in Z\x_2=arctg2+ pi n, n in Zend{array}right$