Question

решить      x^6-14x^6+56x^2-64=0

Answer 1

$x^6-14x^4+56x^2-64=0;\ (x^6-64)-(14x^4-56x^2)=0;\ (x^2-4)(x^4+4x^2+16)-14x^2(x^2-4)=0;\ (x^2-4)(x^4+4x^2+16-14x^2)=0;\ (x-2)(x+2)(x^4-10x^2+16)=0;\ (x-2)(x+2)(x^2-2)(x^2-8)=0;\ x_1=2; x_2=-2; x_3=sqrt{2}; x_4=-sqrt{2}; x_5=-2sqrt{2}; x_6=2sqrt{2}$