Question

Решите пожалуйста неравенство под буквой г

Answer 1

$frac{5x-4}{x+8} geq 15 \ frac{5x-4}{x+8} -15 geq 0 \ frac{5x-4-15x-120}{x+8} geq 0 \ frac{-10x-124}{x+8} geq 0 \ left { {{-10x-124 geq 0} atop {x+8 neq 0}} right. \ left { {{-10x geq 124} atop {x neq -8}} right. \ left { {{x leq -12.4} atop {x neq -8}} right.$