Question

(3а+2)³/(а+2)-(36а+8)/2+а

Answer 1

$frac {(3a+2)^3}{a+2}-frac{36a+8}{2+a}=\ frac {(3a+2)^3-(36a+8)}{2+a}=\ frac{(3a)^3+3*(3a)^2*2+3*(3a)*2^2+2^3-36a-8}{a+2}=\ frac {27a^3+54a^2+36a+8-36a-8)}{2+a}=\ frac{27a^3+54a^2}{a+2}=\ frac{27a(a+2)}{a+2}=27a$