Question

модуль 3(-1.2)+1 целая четыре пятнадцатой+ две третьей

Answer 1

$bigg|3cdot (-1,2)+1 frac{4}{15} bigg|+ dfrac{2}{3}=bigg| -dfrac{36}{10}+ dfrac{20}{15} bigg|+ dfrac{2}{3} =bigg| dfrac{-36cdot3+20cdot2}{30} bigg|+ dfrac{2}{3} =\\\=bigg| -dfrac{68}{30} bigg|+ dfrac{2}{3} = dfrac{68}{30} + dfrac{20}{30} =dfrac{88}{30}=2 frac{28}{30}$