Question

Найти вектор С=1/3d+1/2a

d{-9;3}   a{0;-2}

Answer 1

c=1/3d+1/2a=1/3{-9;3}+1/2{0;-2}={1/3*(-9);1/3*3}+{1/2*0;1/2*(-2)}=

{-3;1}+{0;-1}={-3+0;1+(-1)}={-3;0}

ответ: c{-3;0}