Question

помогите решить уравнение
x^2+3x=4

Answer 1

x^2 +3x -4 = 0
D=9 - 4*(-4) = 9+16 = 25
x1 = (-3+5)/2 = 1
x2 = (-3-5)/2 = -4

Answer 2

$x^{2}+3x=4\ x^{2}+3x-4=0\ x^{2}+px+q=0\ x_{1}+x_{2}=-p \ x_{1}x_{2}=q \ x_{1}+x_{2}=-3 \ x_{1}x_{2}=4 \ x_{1}=-4\ x_{2}=1$

Ответ: -4;1.