Question

Помогите срочно надо!

Answer 1

Решение 

1)      Log_4 (10) + log_4 (1/640)= log_4(10/640) = log_4 (1/64) = log_4 (4^(-3) )= - 3*log_4 (4) = - 3

Ответ: 2) – 3

2)      3log15 (10) * 5log15 (10) = (3*5)log15 (10) = 15log15 (100 = 10

Ответ: 2) 10

3)      Log_3 (b⁻4) = 56,  -4*log_3 b = 56,  log_3 b = - 14

 Log_3 b = - 14

Ответ: 1) -14

4)      m⁴  m³ logm(n)1/6 = m⁴ * m logm(n)1/2 = m⁴ *√n

Ответ: 4) = m⁴ *√n

5)      log23*log32 – log4(2)1/3 = 1 –(1/6) log22 = 1 – 1/6 = 5/6

Ответ: 3) 5/6

6)      log5 log2 log6 6³² + 10lg4 = log5 log2 32+ 4 = log5 log2 (2)⁵ + 4 = log5 5 + 4 = 1 + 4 = 5

Ответ: 5

7)      7log₇3 : log3 (1/3) + log336 – 2log32 = 3 : log₃(3⁻¹) + log₃ 4 + log₃9 - 2log32 = - 1 + 2log33 + 2log32 - 2log32 = - 1 + 2 = 1

Ответ: 1

8)      Log345 / log53 – log315 / log153 = (log33 + log315)/ log53 – (log315*log315)/log53 =

= (1 + log3215) / log53 = (1 + log35)2 / log53

Ответ:  (1 + log35)2 / log53

 

 

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