Question

решите уравнение (х+3)^2+(х-7)^2=2х^2

Answer 1

$\ (x+3)^{2} +(x-7)^{2}=2x^{2} \ \ x^{2} +6x+9 + x^{2} -14x+49=2 x^{2} \ \ 2x^{2} -2 x^{2} -8x+58=0 \ \ -8x=-58 \ \ x= 7.25$
Ответ: х=7,25