Предмет: Химия, автор: DashaLdf

массовая доля химического элемента водорода в молекуле метанола составляет СН4О

Ответы

Автор ответа: ALchemisti

6%
2(4+16+12)=0.06=6%

Автор ответа: IrVB

W% = Ar*n*100%/Mr
Mr(CH4O) = 32
Ar(H) = 1
W(H)% = 1*4*100/32=12,5%

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