Question

сократите дробь (4x)^2*x^-7/x^-8*2x^3

Answer 1

$frac{(4x)^2*x^{-7}}{x^{-8}*2x^3} = frac{16x^2*x^{-7}}{2*x^{-5}} =$

$= 8 frac{x^{-5}}{x^{-5}} = 8$