Question

у²-х²=16
х+у=8
(система)

Answer 1

$left { {{y^2-x^2=16} atop {x+y=8}} right. \ left { {{(y-x)(y+x)=16} atop {x+y=8}} right. \ left { {{8(y-x)=16} atop {x+y=8}} right. \ left { {{y-x=2} atop {x+y=8}} right. \ 2y=10 \ y=5 \ x=8-5=3$

Answer 2

спасибо)