Question

22x-3=3x-22 решите уравнение

Answer 1

$\ frac{22}{x}-3= frac{3}{x}-22 \ \ frac{22-3x}{x} = frac{3-22x}{x} \ \ x(22-3x)=x*(3-22x) \ \ 22x-3 x^{2} =3x-22 x^{2} \ \ 22x-3 x^{2} -3x+22 x^{2} =0 \ \ 19x+19 x^{2} =0 \ \ 19 x^{2} +19x=0 \ \ 19x*(x+1)=0 \ \ 19x=0 \ \ x_{1}=0 \ \ x+1=0 \ \ x_{2} =-1$
Ответ:$\ x_{1}=0 \  \ x_{2} =-1$