Предмет: Алгебра,
автор: katasonovamari
по формулам крамера решить систему уравнений x1+2x2=-1,-3x1+x3=-2,x1+x2+x3=1
Ответы
Автор ответа:
0
Определитель равен ![left[begin{array}{ccc}1&2&0\-3&0&1\1&1&1end{array}right] =
= 0-1-2*(-4)+0=7 left[begin{array}{ccc}1&2&0\-3&0&1\1&1&1end{array}right] =
= 0-1-2*(-4)+0=7](https://tex.z-dn.net/?f=++left%5Bbegin%7Barray%7D%7Bccc%7D1%26amp%3B2%26amp%3B0%5C-3%26amp%3B0%26amp%3B1%5C1%26amp%3B1%26amp%3B1end%7Barray%7Dright%5D+%3D%0A%3D+0-1-2%2A%28-4%29%2B0%3D7)
Ax =![left[begin{array}{ccc}-1&2&0\-2&0&1\1&1&1end{array}right] =1-2*(-2-1)=7
left[begin{array}{ccc}-1&2&0\-2&0&1\1&1&1end{array}right] =1-2*(-2-1)=7](https://tex.z-dn.net/?f=++left%5Bbegin%7Barray%7D%7Bccc%7D-1%26amp%3B2%26amp%3B0%5C-2%26amp%3B0%26amp%3B1%5C1%26amp%3B1%26amp%3B1end%7Barray%7Dright%5D+%3D1-2%2A%28-2-1%29%3D7%0A)
Ay =![left[begin{array}{ccc}1&-1&0\-3&-2&1\1&1&1end{array}right] = -3-3-1=-7 left[begin{array}{ccc}1&-1&0\-3&-2&1\1&1&1end{array}right] = -3-3-1=-7](https://tex.z-dn.net/?f=++left%5Bbegin%7Barray%7D%7Bccc%7D1%26amp%3B-1%26amp%3B0%5C-3%26amp%3B-2%26amp%3B1%5C1%26amp%3B1%26amp%3B1end%7Barray%7Dright%5D+%3D+-3-3-1%3D-7)
Az =![left[begin{array}{ccc}1&2&-1\-3&0&-2\1&1&1end{array}right] =2-2*(-3+2)+3=7 left[begin{array}{ccc}1&2&-1\-3&0&-2\1&1&1end{array}right] =2-2*(-3+2)+3=7](https://tex.z-dn.net/?f=++left%5Bbegin%7Barray%7D%7Bccc%7D1%26amp%3B2%26amp%3B-1%5C-3%26amp%3B0%26amp%3B-2%5C1%26amp%3B1%26amp%3B1end%7Barray%7Dright%5D+%3D2-2%2A%28-3%2B2%29%2B3%3D7)
x1 = 7/7 =1
x2 = (-7)/7 = -1
x3 = 7/7 = 1
Ax =
Ay =
Az =
x1 = 7/7 =1
x2 = (-7)/7 = -1
x3 = 7/7 = 1
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