Question

2sin 225 - ctg 330 * tg405

Answer 1

$2sin225-ctg330cdot tg405=\\=2sin(270-45)-ctg(360-30)cdot tg(360+45)=\\=-2cos45-(-ctg30)cdot tg45=-2cdot frac{sqrt2}{2}+sqrt3cdot 1=sqrt3-sqrt2$