Question

Прошу помогите пожалуйста, очень нужно!)
1)Sin5x = -sinx

2)Sinx/2*sinx=0

Answer 1

1)Sin5x = -sinx
Sin5x + sinx = 0
2*[sin(5x + x)/2]*[cos(5x - x)/2] = 0
[sin(6x)/2]*[cos(4x)/2] = 0
[sin(3x)]*[cos(2x)] = 0
a)   sin3x = 0
3x = πn, n∈Z
x1 = πn/3, n∈Z
b)  cos2x = 0
2x = π/2 + πk, k∈Z
x2 = π/4 + πk/2, k∈Z

2) sin(x/2)*sinx = 0
a)  sin(x/2) = 0
x/2 = πk, k∈Z
x1 = 2πk, k∈Z

b)  sinx = 0
x2 = πn, n∈ Z