Question

(7m-13)^2-(9m+19)^2=0

Answer 1

$(7m-13)^2-(9m+19)^2=0\ (7m-13+9m+19)(7m-13-9m-19)=0\(16m+6)(-2m-32)=0\-4(8m+3)(m+16)=0|:(-4)\(8m+3)(m+16)=0\\8m+3=0\8m=-3\m=-3/8\\m+16=0\m=-16$

Answer 2

спасибо большое