Question

3y^3-12y^2-y+4/9y^4-1=0

Answer 1

3y^3-12y^2-y+4/9y^4-1=0

3y^2(y-4)-(y-4)/9y^4-1=0

(3y^2-1)(y-4)/(3y^2-1)(3y^2+1)=0

y-4/3y^2+1=0

y=4