Question

$-x^{3}y^{4}cdot(-3x^{2}y^{3})^{4}=$

$25a^{10}cdot(-0,2a^{-3}b^{-2})^{2}=$

$(-1frac{1}{3}x^{-4}y^{-3})^{3}cdot(-1frac{1}{8}x^{6}y^{7})^{2}=$$-1frac{1}{3}x^{-4}y^{-3})^{3}cdot(-1frac{1}{8}x^{6}y{7})^{2}=$

Answer 1

$-x^{3}y^{4}(-3x^{2}y^{3})^{4}=-81x^{3}y^{4}x^{8}y^{12}=-81x^{11}y^{16}$

 

$25a^{10}(-0,2a^{-3}b^{-2})^{2}=25*0,04a^{10}a^{-6}b^{-4}=a^{4}b^{-4}$

 

$(-1frac{1}{3}x^{-4}y^{-3})^{3}*(-1frac{1}{8}x^{6}y^{7})^{2}=$

$(-frac{4}{3})^{3}x^{-12}y^{-9}(-frac{9}{8})^{2}x^{12}y^{14}=-frac{64}{27}*frac{81}{64}x^{0}y^{5}=-3y^{5}$