Предмет: Алгебра, автор: адамко

log₂(x²-2x)=3 решите пожалуйста

Ответы

Автор ответа: red321

ОДЗ: x²-2x>0⇒x(x-2)>0⇒x∈(-∞;0)U(2;+∞)

$log_{2}(x^2-2x)=3\x^2-2x=2^3\x^2-2x-8=0\D=4+32=36=6^2\x_1=frac{2+6}{2}=4\x_2=frac{2-6}{2}=-2$

Ответ: x=-2;x=4

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