Question

решите уравнение $x^{3}$ $- 2 x^{2}$ -64х+ 128 = 0

Answer 1

$(x^3 -2x^2)-(64x-128)=0$
$x^{2}(x-2)-64(x-2)=0$
$(x^2-64)(x-2)=0$
$1)x^2-64=0$
$x^2=64$
$/x/= sqrt{64}$
$x=-8$
$x=8$
$2)x-2=0$
$x=2$
$Otvet:-8;8 ; 2.$