Question

2 sin (3x-p/4)=-корень из 2/2

Answer 1

$2sin(3x-frac{pi}{4})=-frac{sqrt{2}}{2}\sin(3x-frac{pi}{4})=-frac{sqrt{2}}{4}\3x-frac{pi}{4}=(-1)^{n}*arcsin(-frac{sqrt{2}}{4})+pi*n, nin Z\3x=(-1)^{n+1}*arcsinfrac{sqrt{2}}{4}+frac{pi}{4}+pi*n, nin Z\x=(-1)^{n+1}*frac{arcsinfrac{sqrt{2}}{4}}{3}+frac{pi}{12}+frac{pi*n}{3}, nin Z$