Question

Сократите дробь:

1) (25-х^2)/(5х-х^2)
2) (3а-12б)/(а^2-8аб+16б^2)



/ - дробь
^ - степень

Answer 1

1) (25-х^2)/(5х-х^2) = [(5 - x)(5 + x)] / [x(5 - x)] = (5 + x) / x

2) (3а -12b)/[(а^2) - 8аb+16(b^2)] = [3*(a - 4b)]  / [(a - 4b)^2] = 3/(a - 4b)