Question

Помогите решить пожалуйста подробно : 3 arcctg(-√3/3)+ 1/2arccos(-√2/2)
tg(arccos√3/2-1/2arctg1/√3)

Answer 1

3arcctg(-√3/3) + (1/2)*arccos(-√2/2) = 3*(2π/3) + (1/2)*(3π/4) = 2π + 3π/8 = 19π/8